If you’re staring at the run-time error “Pure virtual function call” you might be wondering what’s happened. Usually, this is due to calling pure virtual functions from a constructor or destructor. Consider the following code1:
class AllocBase
{
public:
AllocBase() : allocated_(false) {}
virtual ~AllocBase() { Shutdown(); }
void Initialise() {
if (!allocated_) {
Alloc();
allocated_ = true;
}
}
void Shutdown() {
if (allocated_)
Dealloc();
allocated_ = false;
}
// Overridden by subclasses:
virtual void Alloc() = 0;
virtual void Dealloc() = 0;
private:
bool allocated_;
};
class AllocClient : public AllocBase
{
public:
AllocClient() : data_(0) {}
virtual void Alloc() { data_ = new char[10]; }
virtual void Dealloc() { delete[] data_; }
private:
char* data_;
};
int main(int, char**)
{
AllocClient alloc_client;
alloc_client.Initialise();
return 0;
}
Looks fairly innocuous at first glance — the destructor calls Shutdown()
if it hasn’t already
been called. Shutdown()
itself isn’t virtual, but it does call through to the pure virtual Dealloc()
.
This is where the error lies. During construction and destruction, virtual functions are prohibited.
To see why, consider the case of destruction of the AllocClient
object. The compiler must
runs code similar to:
obj->~AllocClient(); // call the AllocClient's destructor
obj->~AllocBase(); // call the base class's destructor
So by the time ~AllocBase()
is called, the AllocClient
aspect of the object has already been
destroyed. Any virtual calls it makes would potentially run code defined in the AllocClient
part
of the object — which is doomed to fail as it will expect the AllocClient
members to be in a usable state.
So how does this generate a pure virtual function call error? Well, what the compiler usually actually runs is:
obj->~AllocClient(); // call the AllocClient's destructor
// Ensure any virtual function calls in ~AllocBase route to
// AllocBase functions, and not any derivee's
obj->__vtable__ = AllocBase::__vtable__;
obj->~AllocBase(); // call the base class's destructor
From here it’s easy to see how the pure virtual calls come about.
In some cases the compiler will catch these at compile time — if you directly call a virtual function in the destructor or constructor, for example. However, GCC and Microsoft’s compiler aren’t smart enough to notice nested calls (and in general it would be extremely hard to prove they actually get called).
Yes, another totally contrived example. ↩
Matt Godbolt is a C++ developer living in Chicago. Follow him on Mastodon or Bluesky.